DeletedUser
Guest
This is the current equation,, (days_on_world + number_of_villages) * X (X is currently 1000)
If you are looking to slow down start up I would say 1000 is prefect.
If you are looking to speed up the idea of no hauls so start up is good and then you dont have the chore of farming which sounds like a better idea to me I would do this
[(number_of_villages) * X]/[(days_on_world)*(.5)]
Where X is 20,000-200,000
Edit to play with the idea more
[(number_of_villages) * X]/[30/(days_on_world)*(1)]
Where X is 40,000, so when you hit 1 month in the world you basically lose farming, which is the aims right.
If you are looking to slow down start up I would say 1000 is prefect.
If you are looking to speed up the idea of no hauls so start up is good and then you dont have the chore of farming which sounds like a better idea to me I would do this
[(number_of_villages) * X]/[(days_on_world)*(.5)]
Where X is 20,000-200,000
Edit to play with the idea more
[(number_of_villages) * X]/[30/(days_on_world)*(1)]
Where X is 40,000, so when you hit 1 month in the world you basically lose farming, which is the aims right.
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